Draw the 1H NMR Spectrum of Ethyl Bromide (CH3CH2Br, C2H5Br)
12.2 هزار بار بازدید -
4 سال پیش
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The three hydrogen atoms on
The three hydrogen atoms on the terminal carbon are split TWICE due to the adjacent CH3 group ... this makes them a triplet.
The two hydrogen atoms on the carbon that also has Bromine on it, are split THREE times due to the adjacent CH3 group. This makes them a quartet.
Low-resolution and high-resolution spectra are both drawn.
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The two hydrogen atoms on the carbon that also has Bromine on it, are split THREE times due to the adjacent CH3 group. This makes them a quartet.
Low-resolution and high-resolution spectra are both drawn.
Check me out: http://www.chemistnate.com
4 سال پیش
در تاریخ 1399/06/12 منتشر شده
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