BERNOULLI'S PRINCIPLE PART _ 01
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10 سال پیش
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7 Active Technology Solutions Pvt.Ltd. is an educational 3D digital content provider for K-12. We also customise the content as per your requirement for companies platform providers colleges etc . 7 Active driving force "The Joy of Happy Learning" -- is what makes difference from other digital content providers. We consider Student needs, Lecturer needs and College needs in designing the 3D & 2D Animated Video Lectures. We are carrying a huge 3D Digital Library ready to use.
BERNOULLI'S PRINCIPLE:A small plastic ball can be made to float above a blowing jet of a fluid. Airplane wings and airfoils are designed in a particular shape. Smoke goes up the chimney. All these examples are comprehensible only when the principle worked out by Daniel Bernoulli is understood.Bernoulli's principle explains that where the velocity of the fluid is high, the pressure is low, and where the velocity is low, the pressure is high.Bernoulli principle states that when a non- viscous, incompressible fluid flows steadily the sum of the pressure energy, kinetic energy and potential energy per unit volume of the fluid remains constant at all points in the path of the flow.Now we derive the equation for Bernoulli principle.Let us consider a non- viscous and incompressible fluid flowing steadily in a tube. The area of cross section of the end at point 1 is A1 and it is at a height h1 from the earth's surface. The area of cross section of the tube at point 2 is A2 and is situated at a height h2 h1 h2.According to the equation of continuity A1v1 = A2v2. In a small time dt, the mass m of the fluid passing the point 1 is ρ A1v1 dt. If we assume the pressure at point 1 be P1, the work done by the fluid that enters the tube at that point is.P1A1v1 dt and this work is positive because the force and displacement are in the same direction. If pressure at 2 is P2, then the work done on the fluid of mass 'm' = ρ A2v2dt at that point is P2A2v2dt and it is negative as force and displacement are in opposite directions. If pressure at 2 is P2, then the work done on the fluid of mass m = ρ A2v2 dt at that points is P2A2v2dt and it is negative as force and displacement are in opposite directions.Therefore the work done on the fluid due to pressure difference.
http://www.7activestudio.com
[email protected]
http://www.7activemedical.com/
[email protected]
http://www.sciencetuts.com/
[email protected]
Contact: +91- 9700061777,
040-64501777 / 65864777
7 Active Technology Solutions Pvt.Ltd. is an educational 3D digital content provider for K-12. We also customise the content as per your requirement for companies platform providers colleges etc . 7 Active driving force "The Joy of Happy Learning" -- is what makes difference from other digital content providers. We consider Student needs, Lecturer needs and College needs in designing the 3D & 2D Animated Video Lectures. We are carrying a huge 3D Digital Library ready to use.
BERNOULLI'S PRINCIPLE:A small plastic ball can be made to float above a blowing jet of a fluid. Airplane wings and airfoils are designed in a particular shape. Smoke goes up the chimney. All these examples are comprehensible only when the principle worked out by Daniel Bernoulli is understood.Bernoulli's principle explains that where the velocity of the fluid is high, the pressure is low, and where the velocity is low, the pressure is high.Bernoulli principle states that when a non- viscous, incompressible fluid flows steadily the sum of the pressure energy, kinetic energy and potential energy per unit volume of the fluid remains constant at all points in the path of the flow.Now we derive the equation for Bernoulli principle.Let us consider a non- viscous and incompressible fluid flowing steadily in a tube. The area of cross section of the end at point 1 is A1 and it is at a height h1 from the earth's surface. The area of cross section of the tube at point 2 is A2 and is situated at a height h2 h1 h2.According to the equation of continuity A1v1 = A2v2. In a small time dt, the mass m of the fluid passing the point 1 is ρ A1v1 dt. If we assume the pressure at point 1 be P1, the work done by the fluid that enters the tube at that point is.P1A1v1 dt and this work is positive because the force and displacement are in the same direction. If pressure at 2 is P2, then the work done on the fluid of mass 'm' = ρ A2v2dt at that point is P2A2v2dt and it is negative as force and displacement are in opposite directions. If pressure at 2 is P2, then the work done on the fluid of mass m = ρ A2v2 dt at that points is P2A2v2dt and it is negative as force and displacement are in opposite directions.Therefore the work done on the fluid due to pressure difference.
10 سال پیش
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