Large Tesla Turbine, live steam test.
167.6 هزار بار بازدید -
10 سال پیش
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This is out third prototype
This is out third prototype of a Tesla turbine. Here we are trying to determine the best running speed of the turbine. Top speed is 6350 rpm at marker 9:52. This is in excess of 414 mph at the outer blade at less than 50 psi. The resonance frequency of the turbine is between 4250 and 4500 rpm. At 4700 rpm the turbine exceeds this frequency, the vibration ceases and the efficiency improves. 5400 looks like a viable operating speed for this 22 inch diameter turbine.
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations.
For starters we are going to be using a rotational kinetic energy calculator. The link is here:
https://www.omnicalculator.com/physic...
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
Large Tesla Turbine, live steam test.
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
Let us stick to some facts and use mathematics and what can be proven through the video and some less than simple calculations.
For starters we are going to be using a rotational kinetic energy calculator. The link is here:
https://www.omnicalculator.com/physic...
Next we will input the relavant data. I am going to use the current point in the video jsut before the RPM slipped the first time. Here is the URL at 46 seconds into the video.
Large Tesla Turbine, live steam test.
At this exact point in time the turbine is rotating at 2718 rpm. The video starts immediately at one second. So there is 45 seconds of acceleration time to achieve this rotational speed.
So we plug this into the calculator as 2718 RPM
Next the unit is made up of 5 total blades. Two of the outer blades are 10 guage and the 3 inner blades are 14 guage.
The weight of 10 guage is .03777 per square inch or 5.43 lbs per square foot,
The weight of 14 guage is .03397 per square inch or 4.75 lbs per square foot.
The discs are all 22 inches in diameter, some math as follows 22 inches diameter / 2 = 11 inch radius.
So the radius squared is 11 x 11 = 121 x Pi (3.14) = 379.94 square inches per plate / 144 square inches in a square foot = 2.638 square feet per plate
Thus, two (2) 10 guage plates at 2.63 sqft. x 5.43 lbs per sqft x 2 plates = 28.56 lbs for the two outer plates.
Also, three (3) 14 guage plates at 2.63 sqft. x 4.75 lbs per sqft. x 3 plates = 37.48 lbs for the three inner plates.
We also have a 5/8 shaft that is 18 inches long and weighs 1.55 pounds
Adding up all the spinning components we get 1.55 lbs + 37.48 lbs + 28.56 lbs = 67.59 pounds x 2.63 sqft. = 177.76 ft * lbs
Input this also into the calculator. when we do this we get an output of 84.29 watt hours rotational kinetic energy (not a subjective figure open to anyones opinions, by the way)
Now we know that it took 45 seconds to achieve this quantified amount of rotational kinetic energy. It started from zero. Thus we added this amount in 46 seconds. and there are 3600 seconds in an hour. So we must divide 84.29 watthours/ 45 seconds = 1.87311 watthours per second was converted from the steam into rotational kinetic energy.
3600 seconds x 1.87311 watthours = 6,743.196 watthours/ 1000 = 6.74 kilowatts per hour or a 9 hp motor could be replaced by this turbine.
10 سال پیش
در تاریخ 1393/10/06 منتشر شده
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