JEE Main Physics Mechanics #15 Pendulum and Error Calculation
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The period of oscillation of a simple pendulum is T=(2pi)(L/g)^(1/2). Measured value of L is 1.0mfrom a meter scale having a minimum division of 1mm and the time of one complete oscillation is 1.95s measured with a stopwatch of 0.01s resolution. The percent error in the determination of g will be:
A) 1.33%
B) 1.30%
C) 1.13%
D) 1.03%
Previous video in this series can be seen at:
JEE Main Physics Mechanics #14 Centri...
Next video in this series can be seen at:
JEE Main Physics Mechanics #16 Simple...
To donate:
http://www.ilectureonline.com/donate
https://www.patreon.com/user?u=3236071
The period of oscillation of a simple pendulum is T=(2pi)(L/g)^(1/2). Measured value of L is 1.0mfrom a meter scale having a minimum division of 1mm and the time of one complete oscillation is 1.95s measured with a stopwatch of 0.01s resolution. The percent error in the determination of g will be:
A) 1.33%
B) 1.30%
C) 1.13%
D) 1.03%
Previous video in this series can be seen at:
JEE Main Physics Mechanics #14 Centri...
Next video in this series can be seen at:
JEE Main Physics Mechanics #16 Simple...
3 سال پیش
در تاریخ 1400/06/10 منتشر شده
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