Minimum Number of K Consecutive Bit Flips | 3 Approaches | Detailed | Leetcode 995 | 3191

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This is the 94th Video of our Playlist "Array 1D/2D : Popular Interview Problems" by codestorywithMIK

In this video we will try to solve an extremely good problem  : Minimum Number of K Consecutive Bit Flips | 3 Approaches | Super Detailed | Leetcode 995 | Leetcode 3191 | codestorywithMIK

I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.

Problem Name : Minimum Number of K Consecutive Bit Flips | 3 Approaches | Super Detailed | Leetcode 995 | codestorywithMIK
Company Tags  : GOOGLE
My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Intervie...
Leetcode 995 Link  : https://leetcode.com/problems/minimum...
Leetcode 3191Link : https://leetcode.com/problems/minimum...


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Summary :
Approach 1: Using Auxiliary Array to Mark Flipped Indices

Time Complexity: O(n)
Space Complexity: O(n)
Description: This approach uses an auxiliary boolean array isFlipped to track whether an index has been flipped. The flipCountFromPastForCurri variable keeps track of the cumulative number of flips affecting the current index. For each index, it adjusts the flip count based on whether the i-k index was flipped and then checks if the current bit needs to be flipped based on the current flip count. If a flip is needed but not possible due to array bounds, it returns -1.
Approach 2: Using the Input Array to Mark Flipped Indices

Time Complexity: O(n)
Space Complexity: O(1)
Description: This approach modifies the input array to mark flipped indices by setting flipped elements to 2. The index_i_kitna_flip_jhela variable is used to track the number of flips affecting the current index. Similar to Approach 1, it adjusts the flip count based on whether the i-k index was flipped (indicated by 2 in the array) and checks if the current bit needs to be flipped. If a flip is needed but not possible due to array bounds, it returns -1.
Approach 3: Using Deque to Mark Flipped Indices

Time Complexity: O(n)
Space Complexity: O(k)
Description: This approach uses a deque (flipQue) to efficiently track the flips within the window of size k. The index_i_kitna_flip_jhela variable keeps track of the cumulative number of flips affecting the current index. For each index, it adjusts the flip count by removing the effect of the flip that goes out of the k-window (front of the deque) and checks if the current bit needs to be flipped. If a flip is needed but not possible due to array bounds, it returns -1. The deque helps in maintaining the flip history within the window efficiently.
These three approaches offer different trade-offs between space complexity and how the flip history is managed, with Approach 2 being the most space-efficient and Approach 1 and 3 offering clear and efficient ways to manage flip history with additional space usage.


✨ Timelines✨
00:00 - Introduction
00:55 - Problem Explanation
06:57 - Thought Process Approach-1
44:05 - Coding Approach-1
46:23 - Approach-2
49:52 - Coding Approach-2
50:43 - Approach-3
01:00:03 - Coding Approach-3
01:02:03 - Solving Leetcode 3191. Minimum Operations to Make Binary Array Elements Equal to One I

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