Practice Problem 2.13 | Find V1&V2 and power dissipated in 3and20k ohm & power supply | Urdu & Hindi

Engineer Abdul Raheem
Engineer Abdul Raheem
20.3 هزار بار بازدید - 3 سال پیش - بسم الله الرحمن الرحيم  
بسم الله الرحمن الرحيم  
In this video you will learn about Practice Problem 2.13 .
Find: (a) V1 and V2,
(b) The power dissipated in the 3k ohm's and 20k ohm's resistors.
(c) The power supplied by the current source.

Use Series and Parallel & Current Division Rule (CDR) Techniques to Solve this problem.

Resistance in Series:

Req = R1 + R2 + R3 +............Rn

Resistance in parallel:

1/Req = 1/R1 + 1/R2 + 1/R3 +.........1/Rn

Current division Rule:
 In Parallel , We know Current are Divided Separately. We Use CDR(Current Division Rule) to find Individual Current.

Formula:
i1 = [IT / (R1 + R2)] * R2

i2 = [IT / (R1 + R2)] * R1

I Hope You Have Enjoyed This Video :)
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Find: (a) V1 and V2, The power dissipated in the 3k ohm's and 20k ohm's resistors, The power supplied by the current source, Practice Problem 2.13 Circuit Analysis, Practice Problem 2.13 Fundamental of Electric Circuit, Practice Problem 2.13 Linear Circuit Analysis, Alexander Practice Problem 2.13, Practice Problem 2.13 DC Network Analysis, Solve Series and Parallel Circuit,  
How to Solve Any Series and Parallel Circuit Problem, resistances in Series and Parallel Combinations,  Engineer Abdul Raheem, Electrical Engineering,


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وَيَسِّرْ لِي أمري
wa yassirli amri.
3 سال پیش در تاریخ 1400/04/05 منتشر شده است.
20,347 بـار بازدید شده
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