Redox Balance MnO4- + Br- = MnO2 + BrO3- || Oxidation Number Method

Aurora Chemistry
Aurora Chemistry
64.1 هزار بار بازدید - 3 سال پیش - This video explains redox balancing
This video explains redox balancing of reaction of permanganate ion with bromide ion in basic medium by Oxidation number method.
Steps to be followed

Step 1 – Assign oxidation number
           Assign Oxidation number for Mn & Br. Oxidation number of Mn in MnO4- is +7 and in MnO2, its oxidation number is reduced to +4. This shows that permanganate ion is the Oxidant and Bromide ion is the reductant.

Step 2 –ION & DON
Segregate the reaction into ION( increase in Oxidation Number )& DON (Decrease in Oxidation number, Then do the following
1.Balance atoms other than Hydrogen& oxygen
2.Balance O.N
Once completing step 2, Rewrite the original redox reaction.

Step 3-  Balance ionic charge by adding H+ for acidic medium & OH- for basic medium
       As the reaction occurs in basic medium and the ionic charges  are not equal on both sides add 2 OH- ions on the right to make ionic charges equal.

Step 4 – Balance Hydrogen atoms by adding H2O
       To balance H- atoms, add 1 H2O molecule on the left side to get balanced redox change.

Step 5 – Check number of Oxygen atoms for final checking of answer

2MnO4-(aq) + Br-(aq) +H2O =2MnO2(s) + BrO3- (aq) + 2OH-(aq)
3 سال پیش در تاریخ 1399/12/11 منتشر شده است.
64,155 بـار بازدید شده
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