How to find the Oxidation Number for Mn in MnSO4

Wayne Breslyn
Wayne Breslyn
65.1 هزار بار بازدید - 5 سال پیش - To find the correct oxidation
To find the correct oxidation state of Mn in MnSO4 (Manganese (II) sulfate), and each element in the molecule, we use a few rules and some simple math.

First, since the MnSO4 molecule doesn’t have an overall charge (like NO3- or H3O+) we could say that the total of the oxidation numbers for MnSO4 will be zero since it is a neutral molecule.

We write the oxidation number (O.N.) for elements that we know and use these to figure out oxidation number for Mn.

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GENERAL RULES
Free elements have an oxidation state of zero (e.g. Na, Fe, H2, O2, S8).
In an ion the all Oxidation numbers must add up to the charge on the ion.
In a neutral compound all Oxidation Numbers must add up to zero.
Group 1 = +1
Group 2 = +2
Hydrogen with Non-Metals = +1
Hydrogen with Metals (or Boron) = -1
Fluorine = -1
Oxygen = -2 (except in H2O2 or with Fluorine)
Group 17(7A) = -1 except with Oxygen and other halogens lower in the group
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We know that Oxygen usually is -2 with a few exceptions. When Oxygen is in a peroxide, like H2O2 (Hydrogen peroxide), it has a charge of -1. When it is bonded to Fluorine (F) it has an oxidation number of +1.

Here it is bonded to Mn so the oxidation number on Oxygen is -2. Using this information we can figure out the oxidation number for the element Mn in MnSO4.
5 سال پیش در تاریخ 1398/06/25 منتشر شده است.
65,152 بـار بازدید شده
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